Question

How do you evaluate `sqrt2+tan^-1(root3(5))`?

Answer 1

2.456, nearly.

Explanation:

Here, inverse tan angle has to be expressed in radian measure.

So, `sqrt2+tan^(-1)(5^(1/3))`

`=1.4142+tan^(-1)1.7100)`, nearly

`=1.4142+(59.681/180 xx pi)`

`=1.4142+1.0416=2.4558`, nearly.