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How do you evaluate $tan^-1(cos((3pi)/2))$ ?

1 Answer

Mar 11, 2016

$=>0$

Explanation:

$tan^-1(cos(3pi/2))$

$=>tan^-1(cos(pi+pi/2))$
$=>tan^-1(0)$
$=>tan^-1(tan(0))$

$=>0$

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