Question

How do you evaluate `tan^-1(sqrt3/3)`?

Answer 1

`tan^-1(sqrt3/3)=pi/6`.

Explanation:

The Defn. of `tan^-1` function is :

`tan^-1x=theta, x in RR iff tantheta=x, theta in (-pi/2, pi/2)`

As `tan (pi/6)=1/sqrt3=sqrt3/3, and, pi/6 in (-pi/2, pi/2)`, we get,

`tan^-1(sqrt3/3)=pi/6`.