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How do you evaluate ${tan}^{- 1} [tan (\frac{5 π}{7})]$ $tan^-1[tan((5pi)/7)]$ ?

1 Answer

Aug 7, 2016

$= \frac{5 π}{7}$ $=(5pi)/7$

Explanation:

${tan}^{- 1} [tan (\frac{5 π}{7})]$ $tan^-1[tan((5pi)/7)]$
$= \frac{5 π}{7}$ $=(5pi)/7$

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