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How do you evaluate ${tan}^{- 1} (tan (\frac{π}{6}))$ $tan^-1(tan((pi)/6))$ ?

1 Answer

Jul 30, 2016

$= \frac{π}{6}$ $=pi/6$

Explanation:

${tan}^{- 1} (tan (\frac{π}{6}))$ $tan^-1(tan(pi/6))$
$= \frac{π}{6}$ $=pi/6$

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