How do you evaluate $tan (arccos (\frac{2}{3}))$ $tan(arccos(2/3))$ ?

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Answer 1 · 2015-06-24T02:47:21

Evaluate: $tan (arccos (\frac{2}{3}))$ $tan (arccos (2/3))$

Calculator gives:

$cos x = \frac{2}{3}$ $cos x = 2/3$ -> arc x = $\pm 48.19$ $+- 48.19$

tan (48.19) = 1.12

tan (-48.19) = - 1.12.

How do you evaluate tan(arccos(23))tan(arccos(2/3))?