How do you evaluate tan[arccos(32)]?

1 Answer
Nov 14, 2015

tan(arccos(32))=33

Explanation:

tan(θ)=sin(θ)cos(θ)
sin(θ)=±1cos2(θ)

During the arccosine range, the sine is always positive so

tan(arccos(32))=1(32)232
tan(arccos(32))=21343
tan(arccos(32))=231343
tan(arccos(32))=234343
tan(arccos(32))=23143
tan(arccos(32))=23(12)3
tan(arccos(32))=33