Question

How do you evaluate the definite integral `int (5-16x^-3) dx` from `[1,2]`?

Answer 1

`int_1^2 (5-16x^-3)d x=1`

Explanation:

`int_1^2 (5-16x^-3)d x=?`

`int_1^2 (5-16x^-3)d x=|5x+16*1/2x^-2|_1^2`

`int_1^2 (5-16x^-3)d x=(5*2+8*2^-2)-(5*1+8*1^-2)`

`int_1^2 (5-16x^-3)d x=(10+8/4)-(5+8/1)`

`int_1^2 (5-16x^-3)d x=14-13`

`int_1^2 (5-16x^-3)d x=1`