How do you evaluate the equation $arcsin(sin ((5pi)/6))$ ?

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Answer 1 · 2015-12-21T11:43:28

$arcsin(sin((5pi)/6)) = pi/6$

$arcsin$ is only defined as having a range $[-pi/2,+pi/2]$

$sin((5pi)/6) = 1/2 = sin(pi/6)$

$arcsin(sin((5pi)/6))=arcsin(1/2) = pi/6$

How do you evaluate the equation arcsin(sin ((5pi)/6))arcsin(sin ((5pi)/6))?