How do you evaluate the expression #(13!)/(9!)#?

1 Answer
Anjali G
Nov 13, 2016

#(13!)/(9!)=17160#

Explanation:

#(13!)/(9!)#

Expand:
#=(13*12*11*10*9*8*7*6*5*4*3*2*1)/(9*8*7*6*5*4*3*2*1)#

Cancel terms:
#=(13*12*11*10*cancel(9*8*7*6*5*4*3*2*1))/cancel(9*8*7*6*5*4*3*2*1)#

#=13*12*11*10#
#=17160#

Related questions
See all questions in Factorial Identities
Impact of this question
5613 views around the world
You can reuse this answer
Creative Commons License