How do you evaluate the expression ${(\frac{5}{y})}^{x}$ $(5/y)^x$ when $x = 2$ $x=2$ and $y = - 1$ $y=-1$ ?

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Answer 1 · 2014-10-01T06:31:47

Substitute the value of x and y in the given expression;

${(\frac{5}{y})}^{x}$ $( 5/y)^x$

given x =2 and y =-1

${(\frac{5}{- 1})}^{2}$ $( 5/-1)^2$

${(- 5)}^{2}$ $( -5) ^2$

( -5 x -5 )

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How do you evaluate the expression (5/y)^x(5y)x(5/y)^x when x=2x=2x=2 and y=-1y=−1y=-1?