How do you evaluate the function $f (x) = 2 x^{2} - 2 x + 9$ $f(x)=2x^2-2x+9$ for f(3/2)?

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How do you evaluate the function $f (x) = 2 x^{2} - 2 x + 9$ $f(x)=2x^2-2x+9$ for f(3/2)?

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Answer 1 · 2018-06-04T09:15:07

$f (\frac{3}{2}) = \frac{21}{2}$ $f(3/2)=21/2$

Explanation:

$to evaluate f (\frac{3}{2}) substitute x = \frac{3}{2} into f (x)$ $"to evaluate "f(3/2)" substitute "x=3/2" into "f(x)$

$f (\frac{3}{2}) = 2 \times {(\frac{3}{2})}^{2} - 2 \times \frac{3}{2} + 9$ $f(color(red)(3/2))=2xx(color(red)(3/2))^2-2xxcolor(red)(3/2)+9$

$\times \times x = 2 \times \frac{9}{4} - 3 + 9$ $color(white)(xxxxx)=2xx9/4-3+9$

$\times \times x = \frac{9}{2} + 6 = \frac{9}{2} + \frac{12}{2} = \frac{21}{2}$ $color(white)(xxxxx)=9/2+6=9/2+12/2=21/2$

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How do you evaluate the function $f (x) = 2 x^{2} - 2 x + 9$ $f(x)=2x^2-2x+9$ for f(3/2)?

1 Answer

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How do you evaluate the function f(x)=2x2−2x+9f(x)=2x^2-2x+9 for f(3/2)?

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How do you evaluate the function $f (x) = 2 x^{2} - 2 x + 9$ $f(x)=2x^2-2x+9$ for f(3/2)?