How do you evaluate the function $f (x) = 3 x^{2} + 3 x - 2$ $f (x) = 3x^2 + 3x -2$ for $f (a) + f (2)$ $f (a) + f (2)$ ?

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How do you evaluate the function $f (x) = 3 x^{2} + 3 x - 2$ $f (x) = 3x^2 + 3x -2$ for $f (a) + f (2)$ $f (a) + f (2)$ ?

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Answer 1 · 2015-11-27T07:25:21

$f (a) + f (2) = 3 a^{2} + 3 a + 14$ $f(a) + f(2) = 3a^2 + 3a + 14$

Explanation:

When evaluating a function $f (x)$ $f(x)$ at some specific value, you simply replace $x$ $x$ with that value wherever $x$ $x$ appears in the function.
So

$f (a) = 3 a^{2} + 3 a - 2$ $f(a) = 3a^2 + 3a - 2$

and

$f (2) = 3 {(2)}^{2} + 3 (2) - 2 = 12 + 6 - 2 = 16$ $f(2) = 3(2)^2 + 3(2) - 2 = 12+6-2 = 16$

Thus

$f (a) + f (2) = (3 a^{2} + 3 a - 2) + 16 = 3 a^{2} + 3 a + 14$ $f(a) + f(2) = (3a^2 +3a - 2) + 16 = 3a^2 + 3a + 14$

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How do you evaluate the function $f (x) = 3 x^{2} + 3 x - 2$ $f (x) = 3x^2 + 3x -2$ for $f (a) + f (2)$ $f (a) + f (2)$ ?

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Explanation:

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