How do you evaluate the function $f(x)=6x^2+2x-12$ for $f(x+1)$ ?

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Answer 1 · 2016-06-14T17:52:11

Function notation states that when given $f(a) = bx^2 + cx$ , the answer is given by evaluating $ba^2 + ca$ , since the $a$ replaces the $x$ .

Thus, we have:

$f(x + 1) = 6(x + 1)^2 + 2(x + 1) - 12$

$f(x + 1) = 6(x^2 + 2x + 1) + 2x + 2 - 12$

$f(x + 1)= 6x^2 + 12x + 6 + 2x + 2 - 12$

$f(x + 1) = 6x^2 + 14x - 4$

Hopefully this helps!

How do you evaluate the function f(x)=6x^2+2x-12f(x)=6x^2+2x-12 for f(x+1)f(x+1)?