How do you evaluate the function $f (x) = x^{2} - 7 x + 10$ $f(x) =x^2- 7x + 10$ and $g (x) = 1 - x^{2}$ $g(x)=1-x^2$ for f(-2)?

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How do you evaluate the function $f (x) = x^{2} - 7 x + 10$ $f(x) =x^2- 7x + 10$ and $g (x) = 1 - x^{2}$ $g(x)=1-x^2$ for f(-2)?

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Answer 1 · 2017-07-02T14:02:09

See a solution process below:

Explanation:

Because we are evaluating $f (- 2)$ $f(-2)$ the information about $g (x)$ $g(x)$ is extraneous.

To evaluate $f (- 2)$ $f(-2)$ we need to substitute $- 2$ $color(red)(-2)$ for every occurrence of $x$ $color(red)(x)$ in $f (x)$ $f(x)$ and calculate the result:

$f (x) = x^{2} - 7 x + 10$ $f(color(red)(x)) = color(red)(x)^2 - 7color(red)(x) + 10$ becomes:

$f (- 2) = {(- 2)}^{2} - (7 \cdot - 2) + 10$ $f(color(red)(-2)) = (color(red)(-2))^2 - (7 * color(red)(-2)) + 10$

$f (- 2) = 4 - (- 14) + 10$ $f(color(red)(-2)) = 4 - (-14) + 10$

$f (- 2) = 4 + 14 + 10$ $f(color(red)(-2)) = 4 + 14 + 10$

$f (- 2) = 28$ $f(color(red)(-2)) = 28$

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How do you evaluate the function $f (x) = x^{2} - 7 x + 10$ $f(x) =x^2- 7x + 10$ and $g (x) = 1 - x^{2}$ $g(x)=1-x^2$ for f(-2)?

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How do you evaluate the function f(x)=x2−7x+10f(x) =x^2- 7x + 10 and g(x)=1−x2g(x)=1-x^2 for f(-2)?

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How do you evaluate the function $f (x) = x^{2} - 7 x + 10$ $f(x) =x^2- 7x + 10$ and $g (x) = 1 - x^{2}$ $g(x)=1-x^2$ for f(-2)?