How do you evaluate the function $h (x) = .2 x^{2} - .6 x - .25$ $h(x)= .2x^2 - .6x - .25$ for $h (- \frac{1}{2})$ $h(-1/2)$ ?

Question

How do you evaluate the function $h (x) = .2 x^{2} - .6 x - .25$ $h(x)= .2x^2 - .6x - .25$ for $h (- \frac{1}{2})$ $h(-1/2)$ ?

1 Answer

Impact of this question

1592 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-22T13:51:07

$h (- \frac{1}{2}) = 0.1$ $h(-1/2) = 0.1$

Explanation:

Substituting $(- \frac{1}{2})$ $(-1/2)$ for $x$ $x$ in $h (x) = 0.2 x^{2} - 0.6 x - 0.25$ $h(x)=0.2x^2-0.6x-0.25$
gives
$XXX h (- \frac{1}{2}) = 0.2 \times {(- \frac{1}{2})}^{2} - 0.6 \times (- \frac{1}{2}) - 0.25$ $color(white)("XXX")h(-1/2) = 0.2xx(-1/2)^2-0.6xx(-1/2)-0.25$

$XXXXXXXX = (0.2 \times \frac{1}{4}) - (- 0.3) - 0.25$ $color(white)("XXXXXXXX")= (0.2xx1/4) - (-0.3) -0.25$

$XXXXXXXX = 0.05 + 0.3 - 0.25$ $color(white)("XXXXXXXX")=0.05+0.3-0.25$

$XXXXXXXX = 0.1$ $color(white)("XXXXXXXX")=0.1$

Science

Math

Humanities

... and beyond

How do you evaluate the function $h (x) = .2 x^{2} - .6 x - .25$ $h(x)= .2x^2 - .6x - .25$ for $h (- \frac{1}{2})$ $h(-1/2)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you evaluate the function h(x)=.2x2−.6x−.25h(x)= .2x^2 - .6x - .25 for h(−12)h(-1/2)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you evaluate the function $h (x) = .2 x^{2} - .6 x - .25$ $h(x)= .2x^2 - .6x - .25$ for $h (- \frac{1}{2})$ $h(-1/2)$ ?