How do you evaluate the function $h(x)=4x-2$ for h(x+2)?

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Answer 1 · 2015-12-30T04:28:31

You have to substitute x for x + 2

h(x) = 4x - 2
h(x + 2) = 4x - 2
h(x + 2) = 4(x + 2) - 2
h(x + 2) = 4x + 8 - 2
h(x + 2) = 4x + 6
h(x + 2) = 2(2x + 3)

How do you evaluate the function h(x)=4x-2h(x)=4x-2 for h(x+2)?