How do you evaluate the function $j (x) = x^{3} - 7 x$ $j(x)=x^3-7x$ when x=3?

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How do you evaluate the function $j (x) = x^{3} - 7 x$ $j(x)=x^3-7x$ when x=3?

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Answer 1 · 2018-05-01T11:00:54

$6$ $6$

Explanation:

$to evaluate substitute x = 3 into j (x)$ $"to evaluate substitute x = 3 into "j(x)$

$\Rightarrow j (3) = {(3)}^{3} - (7 \times 3) = 27 - 21 = 6$ $rArrj(color(red)(3))=(color(red)(3))^3-(7xxcolor(red)(3))=27-21=6$

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How do you evaluate the function $j (x) = x^{3} - 7 x$ $j(x)=x^3-7x$ when x=3?

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How do you evaluate the function $j (x) = x^{3} - 7 x$ $j(x)=x^3-7x$ when x=3?