How do you evaluate the function when x = -3, 0, and 2 for g(x) = -9x + 1?

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Answer 1 · 2017-07-02T00:05:39

See a solution process below:

To evaluate the function you need to replace the value of $x$ for $x$ in the function $g(x)$ .

1) $x = -3$ ; substitute $color(red)(-3)$ for $color(red)(x)$ in $g(x)$ :

$g(color(red)(x)) = -9color(red)(x) + 1$ becomes:

$g(color(red)(-3)) = (-9 * color(red)(-3)) + 1$

$g(color(red)(-3)) = 27 + 1$

$g(color(red)(-3)) = 28$

2) $x = 0$ ; substitute $color(red)(0)$ for $color(red)(x)$ in $g(x)$ :

$g(color(red)(x)) = -9color(red)(x) + 1$ becomes:

$g(color(red)(0)) = (-9 * color(red)(0)) + 1$

$g(color(red)(0)) = 0 + 1$

$g(color(red)(0)) = 1$

2) $x = 2$ ; substitute $color(red)(2)$ for $color(red)(x)$ in $g(x)$ :

Try this one and see if the previous two examples showed you how to evaluate the function. Good luck!