How do you evaluate the function with the given values of $x : dd h (x) = 23 x - 1; d x = \frac{1}{3}; d x = - 1$ $x:color(white)("dd") h(x)=23x-1 ;color(white)("d")x=1/3;color(white)("d") x=-1$ ?

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How do you evaluate the function with the given values of $x : dd h (x) = 23 x - 1; d x = \frac{1}{3}; d x = - 1$ $x:color(white)("dd") h(x)=23x-1 ;color(white)("d")x=1/3;color(white)("d") x=-1$ ?

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Answer 1 · 2018-05-19T09:02:10

$\frac{20}{3} and - 24$ $20/3" and "-24$

Explanation:

$to evaluate substitute the given values for x into h (x)$ $"to evaluate substitute the given values for x into "h(x)$

$h (\frac{1}{3}) = (23 \times \frac{1}{3}) - 1 = \frac{23}{3} - \frac{3}{3} = \frac{20}{3}$ $h(color(red)(1/3))=(23xxcolor(red)(1/3))-1=23/3-3/3=20/3$

$h (- 1) = (23 \times - 1) - 1 = - 23 - 1 = - 24$ $h(color(red)(-1))=(23xxcolor(red)(-1))-1=-23-1=-24$

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How do you evaluate the function with the given values of $x : dd h (x) = 23 x - 1; d x = \frac{1}{3}; d x = - 1$ $x:color(white)("dd") h(x)=23x-1 ;color(white)("d")x=1/3;color(white)("d") x=-1$ ?

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How do you evaluate the function with the given values of x:ddh(x)=23x−1;dx=13;dx=−1x:color(white)("dd") h(x)=23x-1 ;color(white)("d")x=1/3;color(white)("d") x=-1?

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How do you evaluate the function with the given values of $x : dd h (x) = 23 x - 1; d x = \frac{1}{3}; d x = - 1$ $x:color(white)("dd") h(x)=23x-1 ;color(white)("d")x=1/3;color(white)("d") x=-1$ ?