Question

How do you evaluate the indefinite integral `int (2x^2-4x+3)dx`?

Answer 1

#int(2x^2-4x+3)dx=2/3x^3 -2x^2+3x+C, C in RR#

Explanation:

`int(2x^2-4x+3)dx=int2x^2dx-int4xdx+int3dx`
`=2intx^2dx-4intxdx+3intdx`
Also, `int(x^n)dx=(x^(n+1))/(n+1)`
So :`int(2x^2-4x+3)dx=2*x^3/3-4*x^2/2+3x+C=2/3x^3-2x^2+3x+C, C in RR`
\0/ here's our answer !