Question

How do you evaluate the indefinite integral `int (x^3+3x+1)dx`?

Answer 1

The answer is `=x^3/3+3/2x^2+x+C`

Explanation:

We apply

`intx^ndx=x^(n+1)/(n+1)+C`

So,

`int(x^3+3x+1)dx`

`=intx^3dx+int3xdx+int1dx`

`=x^3/3+3/2x^2+x+C`