How do you evaluate the integral int 1/(x(lnx)^2)dx from e to oo? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer Eddie Oct 11, 2016 1 Explanation: int_e^oo 1/(x(lnx)^2)dx = int_e^oo d/dx (- 1/(lnx) )dx = [ - 1/(lnx) ]_e^oo = [ 1/(lnx) ]_oo^e = 1 - 0 = 1 Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of ln(7x)? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of x^2-6x+5 from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral 1/(sqrt(49-x^2)) from 0 to 7sqrt(3/2)? How do you integrate f(x)=intsin(e^t)dt between 4 to x^2? How do you determine the indefinite integrals? How do you integrate x^2sqrt(x^(4)+5)? See all questions in Definite and indefinite integrals Impact of this question 3405 views around the world You can reuse this answer Creative Commons License