Question

How do you evaluate the integral `int x/(x+1)dx` from [0,10]?

Answer 1

`x/(x+1) = (x+1-1)/(x+1) = 1-1/(x+1)`

Explanation:

So,

`int_0^10 x/(x+1) dx = int_0^10 (1-1/(x+1)) dx`

`= {:x-ln(x+1)]_0^10`

`= 10-ln11`