Question

How do you evaluate the limit `(1/(1+h)-1)/h` as h approaches `0`?

Answer 1

`-1`

Explanation:

`(1/(1+h)-1)/h= (1-1-h)/(h(h+1))=-1/(h+1)`

so

`lim_(h->0)(1/(1+h)-1)/h=lim_(h->0)-1/(h+1)=-1`