Question

How do you evaluate the limit `(2p+4)/(3p)` as p approaches `-2`?

Answer 1

Essentially, by Subsitution.

Explanation:

As `p` approaches `-2` the denominator does not go to `0`, so we can simply say:

As `p rarr-2 =>2p+4 rarr 2(-2) + 4 = 0` and `3p rarr -6`, so

`(2p+4)/(3p) rarr 0/(-6) = 0`