How do you evaluate the limit of #lim (1/x-1)/(x-1)# as #x->1#?
1 Answer
Nov 21, 2016
Explanation:
Hence
graph{(1/x-1)/(x-1) [-5.03, 4.97, -2.4, 2.6]}
Hence
graph{(1/x-1)/(x-1) [-5.03, 4.97, -2.4, 2.6]}