How do you evaluate the limit of #lim (2h^3-h^2+5h)/h# as #h->0#?
2 Answers
May 24, 2017
Explanation:
- Both the numerator and denominator are
#0# when#h=0# . We can apply the L'Hopital's rule to find the limit. - The limit is equal to the derivative of numerator over derivative of the denominator.
May 24, 2017
The value of this limit is