How do you evaluate the limit of $lim (2x^2-3x)/(x^3-2x^2+x+6)$ as $x->3$ ?

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Answer 1 · 2018-04-01T20:05:07

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$"the limit in this case can be evaluated by direct substitution"$

$lim_(xto3)(2x^2-3x)/(x^3-2x^2+x+6)$

$=(18-9)/(27-18+3+6)=1/2$

How do you evaluate the limit of lim (2x^2-3x)/(x^3-2x^2+x+6)lim (2x^2-3x)/(x^3-2x^2+x+6) as x->3x->3?