How do you evaluate the limit of $lim (x^2-3x)/(x^3+4x)$ as $x->0$ ?

Question

2627 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-25T02:35:01

Do a little bit of algebraic manipulation.

$=lim_(x->0) (x(x - 3))/(x(x^2 + 4))$

$=lim_(x->0) (x - 3)/(x^2 + 4)$

$=( 0 - 3)/(0^2 + 4)$

$= -3/4$

Hopefully this helps!

How do you evaluate the limit of lim (x^2-3x)/(x^3+4x)lim (x^2-3x)/(x^3+4x) as x->0x->0?