How do you evaluate the limit of #lim (x^3+8)/(x^2-4)# as #x->-2#? Precalculus Limits Two-Sided Limits 1 Answer Ratnaker Mehta Jan 31, 2017 #-3#. Explanation: #"The Rqd. Lim.="lim_(x to -2) (x^3+8)/(x^2-4)# #=lim_(x to -2) {(cancel(x+2))(x^2-2x+4)}/{(cancel(x+2))(x-2)}# #=lim_(x to -2)(x^2-2x+4)/(x-2)# #={(-2)^2-2(-2)+4}/(-2-2)# #=12/-4# #=-3#. Answer link Related questions What is a two-sided limit? How do I find two-sided limits? What is a limit from below? How do you find limits on a graphing calculator? What are some sample limit problems? What is the limit as #t# approaches 0 of #(tan6t)/(sin2t)#? What is the limit as #x# approaches 0 of #1/x#? What is the limit as #x# approaches 0 of #tanx/x#? Is there a number "a" such that the equation below exists? If so what is the value of "a" and its limit. What is the equation below solved for x to the nearest hundredth? See all questions in Two-Sided Limits Impact of this question 20040 views around the world You can reuse this answer Creative Commons License