Question

How do you evaluate the limit `(w+6)/(w^2+8w+16)` as w approaches `-3`?

Answer 1

`lim_(wrarr-3)(w+6)/(w^2+8w+16) = color(green)(3)`

Explanation:

Since `w^2+8w+6 != 0` when `w=-3`

`lim_(wrarr-3)(w+6)/(w^2+8w+16)`

`color(white)("XXX") = ((-3)+6)/((-3)^2+8 * (-3) +16)`

`color(white)("XXX") = 3/1 = 3`