How do you evaluate the sum represented by #sum_(n=1)^(10)n^2# ? Calculus Introduction to Integration Sigma Notation 1 Answer Wataru Sep 21, 2014 Since #sum_{k=1}^n k^2={n(n+1)(2n+1)}/{6}#, we have #sum_{n=1}^{10}n^2={(10)(11)(21)}/6=385# Answer link Related questions How does sigma notation work? How do you use sigma notation to represent the series #1/2+1/4+1/8+…#? Use summation notation to express the sum? What is sigma notation for an arithmetic series with first term #a# and common difference #d# ? How do you evaluate the sum represented by #sum_(n=1)^5n/(2n+1)# ? How do you evaluate the sum represented by #sum_(n=1)^(8)1/(n+1)# ? What is sigma notation for a geometric series with first term #a# and common ratio #r# ? What is the value of #1/n sum_{k=1}^n e^{k/n}# ? Question #07873 Question #117a3 See all questions in Sigma Notation Impact of this question 5334 views around the world You can reuse this answer Creative Commons License