How do you evaluate#x= _6P_3#?

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Answer 1 · 2014-11-04T15:10:56

# P(6, 3) = (6!) / ((6 - 3)!)#

#=> P(6, 3) = (6!) / (3!)#

#=> P(6, 3) = (6 * 5 * 4 * 3 * 2 * 1) / (3 * 2 * 1)#

#=> P(6, 3) = 6 * 5 * 4#

# => P(6, 3) = 120#

Answer 2 · 2014-11-04T15:12:11

#""_6P_3=6cdot5cdot3=90#

(Note: 6 is the factor, and 3 is the total number of factors.)

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