How do you evaluate #x-(absz+x)# when x=6, z=3?
1 Answer
Dec 21, 2016
Explanation:
First step is to evaluate the contents of the bracket and subtract the result from x.
The
#color(blue)"absolute value"# is always positive since it is a measure of the distance of a value from zero.
#"That is " |-4|=|4|=4# since both - 4 and 4 are 4 units from zero.Substitute given values into the expression.
#rArr(|3|+6)=(3+6)=9larr" evaluation of bracket"#
#rArr6-9=-3larr" evaluation of expression"#