How do you evaluate $(x-y)^2-2wz$ if w=6, x=0.4, y=1/2, z=-3?

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Answer 1 · 2017-04-29T02:18:33

See the solution process below:

We need to do the following substitutions into the expression:

$color(red)(6)$ for $color(red)(w)$

$color(blue)(0.4)$ for $color(blue)(x)$

$color(green)(1/2)$ for $color(green)(y)$

$color(purple)(-3)$ for $color(purple)(z)$

$(color(blue)(x) - color(green)(y))^2 - 2color(red)(w)color(purple)(z)$ becomes:

$(color(blue)(0.4) - color(green)(1/2))^2 - (2 * color(red)(6) * color(purple)(-3)) =>$

$(color(blue)(0.4) - color(green)(0.5))^2 - (12 * color(purple)(-3)) =>$

$(-0.1)^2 - (-36) =>$

$0.01 + 36 =>$

$36.01$

How do you evaluate (x-y)^2-2wz(x-y)^2-2wz if w=6, x=0.4, y=1/2, z=-3?