How do you evaluate #(x-y)^2-2wz# if w=6, x=0.4, y=1/2, z=-3?

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Answer 1 · 2017-04-29T02:18:33

See the solution process below:

We need to do the following substitutions into the expression:

#color(red)(6)# for #color(red)(w)#

#color(blue)(0.4)# for #color(blue)(x)#

#color(green)(1/2)# for #color(green)(y)#

#color(purple)(-3)# for #color(purple)(z)#

#(color(blue)(x) - color(green)(y))^2 - 2color(red)(w)color(purple)(z)# becomes:

#(color(blue)(0.4) - color(green)(1/2))^2 - (2 * color(red)(6) * color(purple)(-3)) =>#

#(color(blue)(0.4) - color(green)(0.5))^2 - (12 * color(purple)(-3)) =>#

#(-0.1)^2 - (-36) =>#

#0.01 + 36 =>#

#36.01#