How do you evaluate $y = {sin}^{- 1} (π \frac{3}{2})$ $y=sin^-1(pi3/2)$ ?

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How do you evaluate $y = {sin}^{- 1} (π \frac{3}{2})$ $y=sin^-1(pi3/2)$ ?

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Answer 1 · 2016-10-30T16:28:06

The evaluation cannot be done, because domain for the the inverse sine function is $- 1 \leq x \leq 1$ $-1 <= x <= 1$ and $\frac{3 π}{2}$ $(3pi)/2$ is clearly outside that domain.

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How do you evaluate $y = {sin}^{- 1} (π \frac{3}{2})$ $y=sin^-1(pi3/2)$ ?

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How do you evaluate $y = {sin}^{- 1} (π \frac{3}{2})$ $y=sin^-1(pi3/2)$ ?