Question

How do you expand `log_7(sqrt x^3 /y)`?

Answer 1

`log_7(sqrtx^3 /y)` `=3/2 log_7 x-log_7y`

Explanation:

`log_7(sqrtx^3 /y)`
`=log_7 sqrtx ^3 - log_7y`
`=log_7x^(3/2)-log_7y`
`=3/2 log_7 x-log_7y`-> use property `log_bx^n=nlog_bx`