How do you express $1/(s+1)^2$ in partial fractions?

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Answer 1 · 2016-05-07T10:25:41

$1/(s+1)^2$ is already in its partial fractions form.

Partial fractions of $1/(s+1)^2$ will be of type

$1/(s+1)^2=A/(s+1)+B/(s+1)^2$

= $(A(s+1)+B)/(s+a)^2$

or $1/(s+1)^2=(As+A+B)/(s+a)^2$

Equating coefficients of numerator, we have $A=0$ and $A+B=1$ or $B=1$ .

Hence $1/(s+1)^2=0/(s+1)+1/(s+1)^2$

or $1/(s+1)^2=1/(s+1)^2$

It is apparent that $1/(s+1)^2$ is already in its partial fractions form.

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