How do you express #3sqrt(-48)# as a product of a real number and i?
1 Answer
May 21, 2018
Explanation:
#"using the "color(blue)"laws of radicals"#
#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#
#sqrt(-48)=sqrt(16xx3xx-1)#
#color(white)(xxxx)=sqrt16xxsqrt3xxsqrt-1#
#color(white)(xxxx)=4sqrt3i#
#rArr3(4sqrt3i)=12sqrt3i#