How do you express ln1.5 in terms of Ln2 and Ln3?

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Answer 1 · 2015-07-06T00:30:31

#ln1.5 = ln(3) – ln 2#

#ln1.5 = ln3 – ln 2#

Remember that

#1.5 = 3/2#.

Then

#ln(1.5) = ln(3/2)#

Also, remember that

#ln(x/y) = lnx -lny#

So

#ln(1.5) = ln(3) – ln2#