How do you factor #1/8 + 8x^3#?
1 Answer
Dec 19, 2015
Use the sum of cubes identity to find:
#1/8+8x^3 = (1/2+2x)(1/4-x+4x^2)#
Explanation:
The sum of cubes identity can be written:
#a^3+b^3 = (a+b)(a^2-ab+b^2)#
Both
#1/8+8x^3#
#=(1/2)^3+(2x)^3#
#=(1/2+2x)((1/2)^2-(1/2)(2x)+(2x)^2)#
#=(1/2+2x)(1/4-x+4x^2)#