How do you factor #125a^3-c^3#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Lucio Falabella Jan 11, 2016 #125a^3-c^3=(5a-c)*(25a^2+5ac+c^2)# Explanation: #125a^3-c^3=5^3a^3-c^3=(5a)^3-c^3# Using the difference of two cubes rule: #(b^3-d^3)=(b-d)(b^2+bd+d^2)# with: #b=5a# #d=c# #125a^3-c^3=(5a-c)(5^2a^2+5ac+c^2)=# #=(5a-c)*(25a^2+5ac+c^2)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1516 views around the world You can reuse this answer Creative Commons License