How do you factor #125x^3 + 216#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Meave60 Apr 22, 2015 #125x^3=5x# and #216=6^3# We can use the sum of cubes to factor #(125x^3+216)#. #(a^3+b^3)=(a+b)(a^2-ab+b^2)# #a=5x# #b=6# #(5x+6)((5x)^2-(5x)(6)+6^2)#= #(5x+6)(25x^2-30x+36)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 13176 views around the world You can reuse this answer Creative Commons License