How do you factor #12a^3+2a^2-192a-32#?

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Answer 1 · 2018-04-17T03:23:47

The fully factored form is #2(a-4)(a+4)(6a+1)#.

#color(white)=12a^3+2a^2-192a-32#

#=2a^2(6a+1)-192a-32#

#=2a^2(6a+1)-32(6a+1)#

#=(2a^2-32)(6a+1)#

#=2(a^2-16)(6a+1)#

#=2(a-4)(a+4)(6a+1)#

That's the fully factored form. Hope this helped!