How do you factor $12xy+24xy^2+36xy^3$ ?

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Answer 1 · 2018-03-16T16:09:48

See below

To factorise we must factor out the Highest Common Factor of each term.

Here the HCFs of each term is $12$ , $x$ and $y$ .

$therefore 12xy+24xy^2+36xy^3 = 12xy(1+2y+3y^2)$

When we expand it out we should get the same answer.

Answer 2 · 2018-03-16T16:25:00

$12xy(1+y(2+3y))$

At first take 12xy common out so,

$12xy(1+2y+3y^2$ )

and then for the second 2 terms

$12xy(1+y(2+3y))$

How do you factor 12xy+24xy^2+36xy^312xy+24xy^2+36xy^3?