How do you factor #15x^2 - 16xy+4y^2#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Konstantinos Michailidis Sep 30, 2015 Refer to explanation Explanation: It is #15x^2 - 16xy+4y^2=15x^2-10xy-6xy+4y^2=5x(3x-2y)-2y(3x-2y)=(5x-2y)(3x-2y)# Finally #15x^2 - 16xy+4y^2=(5x-2y)(3x-2y)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 3565 views around the world You can reuse this answer Creative Commons License