How do you factor #16x^2 + 40xy + 25y^2 #? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Konstantinos Michailidis Feb 27, 2016 It is #(4x+5y)^2# Explanation: It is #16x^2 + 40xy + 25y^2=(4x)^2+2*4x*5y+(5y)^2=(4x+5y)^2# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 3553 views around the world You can reuse this answer Creative Commons License