How do you factor #24c^3t^2+26c^2t^3+6ct^4#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Binayaka C. Jul 16, 2016 #2ct^2(3c+t)(4c+3t)# Explanation: #24c^3t^2+26c^2t^3+6ct^4 = 2ct^2(12c^2+13ct+3t^2)=2ct^2(12c^2+9ct+4ct+3t^2)=2ct^2(3c(4c+3t)+t(4c+3t))=2ct^2(3c+t)(4c+3t)#[Ans] Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1262 views around the world You can reuse this answer Creative Commons License