How do you factor #27a^4 - a#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Ratnaker Mehta Jun 16, 2016 #a(3a-1)(9a^2+3a+1).# Explanation: Formula : #x^3-y^3=(x-y)(x^2+xy+y^2).# Expression #=27a^4-a=a(27a^3-1)=a{(3a)^3-1^3}=a(3a-1){(3a)^2+3a*1+1^2}=a(3a-1)(9a^2+3a+1).# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1498 views around the world You can reuse this answer Creative Commons License